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Q.

Two different coils have self-inductances L1= 8 mH and L2=2 mH. The current in one coil is increased at a constant rate. The current in the second coil is also increased at the same constant rate. At a certain instant of time, the power given to the two coils is the same. At that time, the current, the induced voltage and the energy stored in the first coil are i1, V1, W1 respectively. Corresponding values for the second coil at the same instant are i2, V2, W2 respectively. Then,

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a

i1i2=4

b

W1W2=14

c

i1i2=14

d

V1V2=4

answer is A, C, D.

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Detailed Solution

Potential difference across an inductor: 

VL if rate of change of current is constant V=-Ldidt

V2V1=L2L1=28=14 V1V2=4

Power given to the two coils in same, i.e.

V1i1=V2i2 i1i2=V2V1=14

Energy stored, W=12Li2

W2W1=L2L1i2i12=1442 W1W2=14

The correct options are (1), (3) and (4).

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