Two different wires have specific resistivity's, lengths, area of cross-sections are in the ratio 3:4, 2:9 and 8:27. Then the ratio of resistance of two wires is

GivenRatio of specific resistance $\frac{{\mathrm{\rho }}_1}{{\mathrm{\rho }}_2}=\frac{3}{4}$ Ratio of lengths  $\frac{{\mathrm{\ell }}_1}{{\mathrm{\ell }}_2}=\frac{2}{9}$
Ratio of area of cross-sections$\frac{{\mathrm{A}}_1}{{\mathrm{A}}_2}=\frac{8}{27}$  Ratio of resistance  $\frac{{\mathrm{R}}_1}{{\mathrm{R}}_2}=?$
$\frac{{\mathrm{R}}_1}{{\mathrm{R}}_2}=\frac{{\mathrm{\rho }}_1}{{\mathrm{\rho }}_2}\frac{{\mathrm{\ell }}_1}{{\mathrm{\ell }}_2}\times \frac{{\mathrm{A}}_2}{{\mathrm{A}}_1}\left(\because \mathrm{R}=\frac{\mathrm{\rho l}}{\mathrm{A}}\right)=\frac{3}{4}\times \frac{2}{9}\times \frac{27}{8}=\frac{9}{16}$