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Q.

Two dipoles each of moment 5 × 10–12 Cm form a cross with their axis (-to+) along the coordinate axes. The potential at a point 20cm away in a direction making an angle of 30o with axis is

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a

1.12 V

b

2.4 V

c

2.12 V

d

1.536 V

answer is D.

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Detailed Solution

V=V1+V2=14πε0Pcos⁡300r2+14πε0Pcos⁡90−300r2=P4πε0r232+12=9×109×5×10−12×2.7320.2×0.2×2
=1.536V

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