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Q.

Two distinct chords drawn from the point (p, q) on the circle x2+y2=px+qy, where pq0 are bisected by the xaxis. Then  

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a

|p|=|q|

b

p2>8q2

c

p2<8q2

d

p2=8q2

answer is D.

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Detailed Solution

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Suppose chord bisect at M(λ,    0) , then other end point of chord is (h,    q) where λ=p+h2

Which lie on x2+y2=px+qy or h2+q2=phq2   h2ph+2q2=0

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for two chords, Δ>0p24.1.2q2<0p2>8q2

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