Two electric bulbs A and B are rated 60 and 100 W, respectively. If they are connected in parallel to the same source, then 

Given $P_A=60W,P_B=100W.$We know that current flowing through the bulb is $I=P/V.$ We also know that as both the bulbs  are connected in parallel, potential difference (V) across both  the bulbs is the same. Thus, $I\propto P.$ Since the power of bulb B is greater than that of bulb A, bulb B draws more current than bulb A.