Two electric bulbs marked 25W-220V and 100W-220V are connected in series to a 440V supply. Which of the bulbs will fuse?

$\begin{array}{l}\text{ The current upto which bulb of marked }25 \text{W}-220 \text{V},\text{ will not fuse }\\ I_1=\frac{P_1}{ {\text{V}}_1}=\frac{25}{220}\text{Amp}\\ {\text{ Similarly, I}}_2=\frac{P_2}{V_2}=\frac{100}{220}\text{ Amp }\\ \text{ The current flowing through the circuit }\\ I=\frac{440}{R_{eff}}\\ {\text{R}}_{\text{eff }}=R_1+R_2\\ R_1=\frac{V_1^2}{P_1}=\frac{{\left(220\right)}^2}{25};R_2=\frac{V_2^2}{P_2}=\frac{{\left(220\right)}^2}{100}\\ \Rightarrow I=\frac{440}{\frac{{\left(220\right)}^2}{25}+\frac{{\left(220\right)}^2}{100}}=\frac{440}{{\left(220\right)}^2[\frac{1}{25}+\frac{1}{100}]}\\ \Rightarrow I=\frac{40}{220}\text{Amp}\\ \because I_1(=\frac{25}{220}A)<I(=\frac{40}{220}A)<I_2(=\frac{100}{200}A)\\ \text{ Thus the bulb marked }25 \text{W}-220\text{ will fuse. }\end{array}$