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Q.

Two electric bulbs whose resistances are in the ratio of 1 : 2 are connected in parallel to a constant voltage source. The powers dissipated in them have the ratio

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a

1:4

b

1:2

c

1:1

d

2:1

answer is C.

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Detailed Solution

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Power dissipated, $P = \frac{E^{2}}{R}$

$\frac{P_{1}}{P_{2}} = \frac{\frac{E^{2}}{R_{1}}}{\frac{E^{2}}{R_{2}}} = \frac{R_{2}}{R_{1}}$

Given, $\frac{R_{1}}{R_{2}} = \frac{1}{2}$

$\frac{P_{1}}{P_{2}} = \frac{2}{1}$

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Two electric bulbs whose resistances are in the ratio of 1 : 2 are connected in parallel to a constant voltage source. The powers dissipated in them have the ratio