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Two electric charges of 9 µC and -3 µC are placed 0.16 m apart in air. There will be a point P at which electric potential is zero on the line joining the two charges and in between them. The distance of P from 9 µC charge is

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0.08 m

0.12 m

0.14 m

0.06 m

answer is B.

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Detailed Solution

$\begin{array}{l} X = \frac{d}{1 - \frac{q_{big}}{q_{small}}} = \frac{0 .16}{1 + \frac{9}{3}} = 0 .04 m from - 3 μC . \\ ∴ 0 .12 m from 9 μC \end{array}$

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