Two elements X and Y have atomic weight of 14 and 16. They form a series of compounds A, B, C, X, Y is present in the ratio 1:2:3:4:5. If the compound A has 28 parts by weight of X and 16 parts by weight of Y, then the compound C will have 28 parts by weight of X and

Let us see below the mass ratio of elements in different compounds.
$\begin{array}{l}\mathrm{A} \hspace{0.17em}: \mathrm{B} : \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em} \mathrm{C} : \hspace{0.17em} \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\mathrm{D} : \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em} \mathrm{E}\\ 1\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}:\hspace{0.17em}\hspace{0.17em} \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}2\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}:\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em} 3\hspace{0.17em}\hspace{0.17em}:\hspace{0.17em}\hspace{0.17em} \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em} 4\hspace{0.17em}\hspace{0.17em}:\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em}\hspace{0.17em} 5\\ {\mathrm{N}}_2\mathrm{O}\hspace{0.17em} \hspace{0.17em}\hspace{0.17em}{\mathrm{N}}_2{\mathrm{O}}_2\hspace{0.17em}\hspace{0.17em}\hspace{0.17em} {\mathrm{N}}_2{\mathrm{O}}_3\hspace{0.17em}\hspace{0.17em} {\mathrm{N}}_2{\mathrm{O}}_4\hspace{0.17em}\hspace{0.17em} {\mathrm{N}}_2{\mathrm{O}}_5\end{array}$
C will law 28 parte by weight of X and 48 parte by weight of Y.
Note: Here ‘X’ represents element N and ‘Y’ represents element O.