Two elements X (atomic mass 16) and Y (atomic mass 14) combine to form compounds A, B and C in which the ratio of weight of Y combines with a fixed mass of X is 1 : 3 : 5 respectively.
If 32 parts by mass of X combines with 84 parts by mass of Y in B, then in C, 16 parts by mass of X will combine with

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84 parts by mass of Y

42 parts by mass of Y

70 parts by mass of Y

14 parts by mass of Y

answer is C.

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Detailed Solution

32 parts by mass of X combines with 84 parts by mass of Y to form B. Hence, 16 parts of the mass of X combine with 42 parts by mass of Y. The ratio of Y in B and C is 3:5.

16 parts by mass of X combines with 70 parts by mass of Y to form C

$42 \times \frac{5}{3} = 70$
So, the correct option is C

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