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Two ends A and B of a smooth chain of mass m and length l are situated as shown in figure. If an external agent pulls A till it comes to same level of B, work done by external agent is

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$\frac{mgl}{9}$

$\frac{mgl}{15}$

$\frac{mgl}{36}$

None of the above

answer is A.

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Detailed Solution

Final figure is shown below. It can be obtained as follows.

We can assume that a part of length l/6 is cut from the lower portion of side B, and put below A.

Mass of this part $= \frac{m}{6}$

This part rises by $= \frac{l}{6}$

Work done = Increase in PE $= \frac{mgl}{36}$

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