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Two engines pass each other moving in opposite directions with uniform speed of 30m/s one of them is blowing a whistle of frequency 540 Hz calculate the frequency heard by driver of second engine before they pass each other speed of sound is 330 m/sec.

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450 Hz

540 Hz

270 Hz

648 Hz

answer is D.

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Detailed Solution

Apparent frequency $f' = |\frac{v + v_{0}}{v - v_{s}}| f$

$v_{s} = v_{0} = 30 m / s$

$v = 330 m / s$

$f = 540 Hz$

$\begin{array}{l} f' = [\frac{330 + 30}{330 - 30}] 540 \\ = \frac{360 \times 540}{300} \\ = 12 \times 54 = 648 \end{array}$

$f' = 648 Hz$

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