Q.

Two equal charges q are placed at a distance of 2a and a third charge -2q is placed at the midpoint. The potential energy of the system is

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a

q28πε0a

b

9q28πε0a

c

6q28πε0a

d

-7q28πε0a

answer is C.

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Detailed Solution

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Usystem =14πε0(q)(-2q)a+14πε0(-2q)(q)a+14πε0(q)(q)2a Usystem =-7q28πε0a

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