Q.

Two equal masses m are attached by a string. One mass lies at radial distance r from the center of a horizontal turntable which rotates with constant angular velocity ω , while the second hangs from the strings inside the turntable’s hollow spindle (see figure). The coefficient of static friction between the turntable and the mass lying on it is  μs=0.5. The maximum and minimum values of r such that the mass lying on the turntable does not slide are  rmax,rmin. Find the ratio rmax/rmin .
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answer is 3.

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Detailed Solution

mgμmg=mrminω2 _____________(1)
mg+μmg=mrmaxω2 _____________(2)
 (2)(1)rmaxrmin=1+μ1μ=3

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Two equal masses m are attached by a string. One mass lies at radial distance r from the center of a horizontal turntable which rotates with constant angular velocity ω , while the second hangs from the strings inside the turntable’s hollow spindle (see figure). The coefficient of static friction between the turntable and the mass lying on it is  μs=0.5. The maximum and minimum values of r such that the mass lying on the turntable does not slide are  rmax,rmin. Find the ratio rmax/rmin .