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Two equal resistances when connected in series to a battery consume electric power of 60 W. If these resistances are now connected in parallel combination to the same battery, the electric power consumed (in watt) is

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answer is 240.

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Detailed Solution

The power consumed when two resistance are in series combination is $V^{2} / 2 R = 60 W \Rightarrow V^{2} / R = 120 W$

When the two resistance are connected in parallel combination, power consumed is $2 V^{2} / R = 120 (2) = 240 W$

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