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Two events A and B are such that P(B) = 0.55 and $P (A B') = 0.15.$ The probability of occurence of at least one of event is

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0.70

0.35

0.30

0.20

answer is A.

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Detailed Solution

$\begin{array}{rcl} P (B) & = & 0.55 P (A \cap B) = 0.15 \end{array}$

$\begin{array}{rcl} P (A) - P (A \cap B) & = & 0.15 \end{array}$

$\begin{array}{rcl} P (A \cup B) & = & P (A) + P (B) - P (A \cap B) \\ = & 0.15 + 0.55 = 0.70 \end{array}$

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