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Two events A and Bare said to be independent, if

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A and B are mutually exclusive

$P (A^{'} B^{'}) = [1 - P (A)] [1 - P (B)]$

$P (A) = P (B)$

$P (A) + P (B) = 1$

answer is B.

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Detailed Solution

$P (A^{'} and B) = [1 - P (A)] \cdot [1 - P (B) = P (A^{'}) \cdot P (B^{'})$

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