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Two flasks A and B of equal volume containing equal masses of $H_{2}$ and $C H_{4}$ gases are at 100 K and 200 K temperature, respectively. Which of the following is true about the total KE

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Total KE of

H_{2}

is four times that of

C H_{4}

Total KE of

C H_{4}

is four times that of

H_{2}

Total KE of

H_{2}

is two times that of

C H_{4}

Total KE of

C H_{4}

is two times that of

H_{2}

answer is A.

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Detailed Solution

\frac{K . E o f H_{2}}{K . E o f C H_{4}} = \frac{\frac{3}{2} n R T}{\frac{3}{2} n R T}

$= \frac{\frac{3}{2} \frac{W}{M . W} R T}{\frac{3}{2} \frac{W}{M} R T} = \frac{\frac{W}{2} \times 100}{\frac{W}{16} \times 200}$

$\frac{100}{2} \times \frac{16}{200_{2}} = 4$

$= K . E o f H_{2} = 4 K . E o f C H_{4}$

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Two flasks A and B of equal volume containing equal masses of H2 and CH4 gases are at 100 K and 200 K temperature, respectively. Which of the following is true about the total KE

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Two flasks A and B of equal volume containing equal masses of $H_{2}$ and $C H_{4}$ gases are at 100 K and 200 K temperature, respectively. Which of the following is true about the total KE