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Two flasks of equal volume are connected by a narrow tube (of negligible volume) all at 27° C and contain 0.70 moles of 'H₂ at 0.5 atm. One of the flask is then immersed into a bath kept at 127° C, while the other remains at 27° C. The number of moles of H₂ in flask 1 and flask 2 (at 127° C) are:

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Moles in flask 1 = 0.4, Moles in flask 2 = 0.3

Moles in flask 1 = 0.2, Moles in flask 2 = 0.5

Moles in flask 1 == 0.3, Moles in flask 2 = 0.4

Moles in flask 1 = 0.4. Moles in flask 2 = 0.2

answer is A.

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Detailed Solution

It is known that;

$n_{1} = \frac{0.5714 \times 17.241}{0.0821 \times 400} ≃ 0.3$

$∴ n_{2} = 0.4$

The value of volume after putting the value in the above formula is Moles in flask 1 = 0.4, Moles in flask 2 = 0.3

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