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Two flasks of equal volume is connected by a narrow tube (of negligible volume) contains a certain amount of $N_{2}$ gas 2 atm and $27^{0} C$ . The 1st flask is then immersed into a bath kept at $47^{0} C$ while the 2nd flask is immersed into a bath kept at $127^{0} C$ . The ratio of the number of moles of $N_{2}$ in 1st flask to the 2nd flask after sometime will be:

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$5 : 4$

$2 : 3$

$3 : 2$

$4 : 5$

answer is A.

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Detailed Solution

Total number of moles remains constant

$\begin{aligned} n_{1} = \frac{P V}{R T_{1}} n_{2} = \frac{P V}{R T_{2}} \\ \frac{n_{1}}{n_{2}} = \frac{T_{2}}{T_{1}} = \frac{400}{320} = \frac{5}{4} \end{aligned}$

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