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Two flasks of equal volumes have been joined by a narrow tube of negligible volume. Initially both
the flasks are 300 K and totally 9 mole of gas is present. One of the flasks is then placed in a
thermostat at 600K. How many moles of gas is present in hot bulb.

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answer is 3.

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Detailed Solution

Total initial moles = total final moles

$\begin{array}{l} \frac{n_{hot}}{n_{cold}} = \frac{\frac{P \times V}{R \times 600}}{P \times V / R \times 300} = \frac{1}{2} \\ n_{hot} = \frac{1}{3} \times 9 = 3 moles \end{array}$

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