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Q.

Two forces 3 N and 2 N are at an angle θ such that the resultant is R. The first force is now increased to 6N and the resultant becomes 2R.  The value of θ is

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a

60∘

b

30∘

c

90∘

d

120∘

answer is D.

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Detailed Solution

A=3, B=2N then

R=A2+B2+2ABcosθR=9+4+12cosθ

Now A=6N, B=2N then

2R=36+4+24cosθ

From Eq.s (i) and (ii), we get cosθ=12⇒ θ=1200

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Two forces 3 N and 2 N are at an angle θ such that the resultant is R. The first force is now increased to 6N and the resultant becomes 2R.  The value of θ is