Q.

Two full runs of the circular scale of a screw gauge cover a distance of 1 mm on its main scale. The total number of divisions on the circular scale is 50. Further it is found that the screw gauge has a zero error of – 0.03 mm. While measuring the diameter of a thin wire, a student notes the main scale reading of 3 mm and the number of circular scale divisions in line with the main scale as 35. The diameter of the wire is

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a

3.67 mm

b

3.73 mm

c

3.38 mm

d

3.32 mm

answer is A.

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Detailed Solution

The least count of screw gauge is 0.5mm50=0.01mm ;
The main scale reading is 3 mm.
The vernier scale reading is 35.
Observed reading = 3 + 0.35 = 3.35.
Zero error = - 0.03
Therefore, the actual diameter of the wire is 3.35−(−0.03) = 3.38 mm.

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