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Two full turns of the circular scale of a screw gauge cover a distance of 1 mm on its main scale. The total number of divisions on the circular scale is 50. Further, the screw gauge has a zero error of –0.03 mm. If main scale reading is 3 mm and circular scale reading is 35 during the measurement of diameter of a wire. Then diameter of wire is $(3 + \frac{x}{100}) m m .$ The value of $x$ is $19 n$ then $n$ is

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Detailed Solution

$L . C = \frac{1}{50 \times 2} = 0.01 m m$

$∴$ Diameter $= 3 + 35 \times 0.01 + 0.03 = 3 . 38mm = (3 + \frac{38}{100}) m m$

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