Two gaseous samples were analyzed. One contained 1.2 g of carbon and 3.2 g of oxygen. The other contained 27.3% carbon and 72.7% oxygen. The experimental data is in accordance with

Percentage of carbon:

$\frac{1.2}{1.2+3.2}\times 100=27.27\%$

Percentage of oxygen:

$\frac{3.2}{1.2+3.2}\times 100=72.72\%$

For the second sample, the percentages of carbon and oxygen are 27.3% and 72.7% respectively.

Both the samples have an equal percentage of the two elements. This follows the law of definite proportions.