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Q.

Two gases ‘A’ and ‘B’ have there Henry’s constant (K_H) values as 44 kPa and 66 kPa at 293 K. At 293 K, if ‘A’ and ‘B’ are dissolved in water where the partial pressure ratio of A to B is 1 : 3 then the ratio of solubility of A to B would B would be

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a

9 : 2

b

2 : 1

c

2 : 9

d

1 : 2

answer is A.

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Detailed Solution

$p = K_{H} X$

$\frac{p_{1}}{p_{2}} = \frac{K_{H_{1}}}{K_{H_{2}}} \times \frac{χ_{1}}{χ_{2}}$

$\frac{1}{3} = \frac{44}{66} \times \frac{χ_{1}}{χ_{2}}$

= 1:2

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Two gases ‘A’ and ‘B’ have there Henry’s constant (KH) values as 44 kPa and 66 kPa at 293 K. At 293 K, if ‘A’ and ‘B’ are dissolved in water where the partial pressure ratio of A to B is 1 : 3 then the ratio of solubility of A to B would B would be