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Two gases A and B having the molar mass 60 and 45 g ${mol}^{- 1}$ , respectively are enclosed in a vessel. The weight of A is 0.5 g and that of B is 0.2 g. The total pressure of the mixture is 750 mm. The partial pressure of gas A and B respectively are

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260 mm,490 mm

l90mm, 560 mm

490 mm, 260 mm

520 mm, 290 mm

answer is C.

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Detailed Solution

Number of moles of A = $\frac{0.50}{60} = 0.0083$

Number of moles of B $= \frac{0.20}{45} = 0.0044$

$Total pressure = 750 mm of Hg$

$p_{A} = mole fraction of A \times total prelssure$

$= \frac{0.0083}{0.0083 + 0.0044} \times 750 = 490 mm$

$p_{B} = 750 - 490 = 260 mm$

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