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Two holes are made in the side of the tank such that the jets of water flowing out of them meet at the same point on the ground. If one hole is at a height of 5 cm above the
bottom, then the distance of the other hole from the top surface of water is

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$\frac{3}{2} c m$

$\sqrt{6} c m$

$\sqrt{3} c m$

5 cm

answer is D.

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Detailed Solution

$x = \sqrt{2 g h_{1}} \times \sqrt{\frac{2 h_{2}}{g}} or x = 2 \sqrt{h_{1} h_{2}}$

Now, imagine a hole at a depth h₂ below the free surface of the liquid. The height of this hole will be h₁. Clearly, x remains the same.

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