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Q.

Two hollow conducting spheres of radii R₁ and R₂ (R₁>>R₂) have equal charges. The potential would be

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a

more on bigger sphere

b

dependent on the material property of the sphere

c

more on smaller sphere

d

equal on both the spheres

answer is A.

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Detailed Solution

$\begin{array}{l} V_{1} = kq (\frac{1}{R_{1}}) \\ V_{2} = \frac{kq}{R_{2}} \end{array}$

(R₁>>R₂)

Thus, $V_{1} < V_{2}$

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Two hollow conducting spheres of radii R1 and R2 (R1>>R2) have equal charges. The potential would be