Two I-order reactions have half-lives in the ratio 8 : 2. Calculate the ratio of time intervals $t_{1}$ , $t_{2}$ . Where $t_{1}$ is the time period for 25 % completion of the first reaction and $t_{2}$ , for 75 % completion of the second reaction.

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

0.199 : 1

0.311 : 1

0.420 : 1

0.273 : 1

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The time intervals,

$\begin{array}{r} t_{1} = \frac{3}{\ln 2} \times \ln (\frac{100}{75}) \\ t_{2} = \frac{2}{\ln 2} \times \ln (\frac{100}{25}) \end{array}$

The ratio of time intervals,

$\frac{t_{1}}{t_{2}} = \frac{3}{2} [\frac{0 .6 - 0 .48}{0 .6}] \frac{t_{1}}{t_{2}} = 0.311$

JEE

NEET

Foundation JEE

Foundation NEET

CBSE