Two ice skaters A and B approach each other at right angles. Skater A has a mass 30 kg and velocity 1 m/s and skater B has a mass 20 kg and velocity 2 m/s. They meet and cling together. Then final velocity of the couple is

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2 m/s

1.5 m/s

2.5 m/s

1 m/s

answer is D.

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Detailed Solution

Momentum of skater $A = 30 \times 1 = 30 kg m / s$
Momentum of skater $B = 20 \times 2 = 40 kg m / s$
They are at right angles to each other.
Resultant momentum = p
$\begin{array}{l} \Rightarrow p = \sqrt{(30)^{2} + (40)^{2}} \\ \Rightarrow p = 50 kgm / s \end{array}$
$∴ Final velocity = \frac{p}{Total mass} = \frac{50}{(30 + 20)} = 1 m / s$

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