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Two ice skaters A and B approach each other at right angles. Skater A has a mass 30 kg and velocity 1 m/s and skater B has a mass 20 kg and velocity 2 m/s. They meet and cling together. Their final velocity of the couple is

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2 m/s

1.5 m/s

1 m/s

2.5 m/s

answer is C.

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Detailed Solution

$\bar{P_{A}} + \bar{P_{B}} = \bar{P}$

$(30 \times 1) \hat{i} + (20 \times 2) \hat{j} = (m_{1} + m_{2}) \bar{V} = 50 \bar{V}$

$50 \bar{V} = 30 \hat{i} + 40 \hat{j}$

$| \bar{V} | = \frac{50}{50} = 1 m / s$

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