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Two ideal batteries and two ammeters are arranged as shown in figure

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If $E_{2} > E_{1},$ then current in ammeters will flow in opposite directions

Readings of both ammeters can be same if $E_{2} > E_{1}$ provided $R_{2} < R_{1}$

Readings of both ammeters can be same if $E_{1} > E_{2}$

Readings of both ammeters can be same if $E_{2} > E_{1}$ provided $R_{2} > R_{1}$

answer is A, B, D.

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Detailed Solution

By applying Kirchhoff’s law, we can obtain

$I_{2} = \frac{E_{2}}{R_{2}} a n d I_{1} = \frac{E_{1} - E_{2}}{R_{1}}$

If $E_{1} > E_{2}, I_{1} a n d I_{2}$ can be the same for some value of $R_{1} a n d R_{2},$ hence (1) is correct.

For (2), if $E_{2} > E_{1}, t h e n I_{1}$ will be in the direction opposite to that shown in the figure and magnitude of $I_{1} w i l l b e I_{1} = (E_{2} - E_{1}) / R_{1} .$ Now $I_{1} a n d I_{2}$ can be same only if $R_{1} < R_{2}$

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