Two ideal batteries having emf $E_{1} a n d E_{2}$ are connected as shown in figure. The values of resistances are chosen in such a way that ammeter reading is zero. The reading of voltmeter will be (consider the meters to be ideal)

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$E_{1}$

$E_{2}$

In between $E_{1} a n d E_{2}$

Nothing can be predicted about voltmeter reading from the given information

answer is B.

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Detailed Solution

The ammeter is not showing any reading. It means the potential drop across CB due to $E_{1}$ is equal to that of the emf $E_{2} .$ And this is the reading of the voltmeter.

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