Two identical balls are shot upward one after another at an interval of $2 s$ along the same vertical line with same initial velocity of 40 $m s^{- 1}$ . The height at which the balls collide is

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75 m

125 m

100 m

50 m

answer is B.

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Detailed Solution

$s_{1} = s_{2}$
$∴ (40) t - \frac{1}{2} \times 10 \times t^{2} = (40) (t - 2) - \frac{1}{2} \times 10 \times {(t - 2)}^{2}$
Solving this equation, we get
$t = 5 s$
Then

$s_{1} = (40) (5) - \frac{1}{2} \times 10 \times (5)^{2} = 75 m$

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