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Two identical balls P and Q are projected with same speeds in a vertical plane from same point O making projection angles with horizontal 30º and 60º respectively and they fall directly on a plane AB at points P' and Q' respectively. Which of the following statements is true about distances as given in options ?

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$A P^{'} > A Q^{'}$

$A P^{'} < A Q^{'}$

$A P^{'} \leq A Q^{'}$

As these are complimentary projection angles, then $A P^{'} = A Q^{'} .$

answer is A.

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Detailed Solution

Projection angle of ball P = 30° and projection angle of ball Q = 60°
Question Image
For complimentary angle ranges, OR is same for P and Q as O and R are on same horizontal plane.
From figure we can say that $A P^{'} > A Q^{'}$

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