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Two identical bar magnets are joined to form a cross. If this combination is suspended freely in a uniform field the angles made by the magnets with field direction are respectively

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60°, 30°

37°, 53°

45°, 45°

20°, 70°

answer is C.

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Detailed Solution

$τ = MBsin θ, τ_{1} = τ_{2}$ $\Rightarrow θ_{1} = θ_{2} . A l s o θ_{1} + θ_{2} = 90^{0}$

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