Two identical blocks A and B are placed on two inclined planes as shown in diagram. Neglect air resistance and other friction. Read the following statements and choose the correct options.

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Work done by external agent to move block slowly from position B to O is negative

Kinetic energy of 'A' on sliding to J will be greater than the kinetic energy of B on falling to M.

If both inclines are rough with a small but same coefficient of friction, and A & B are released to slide on the inclines, they reach the bottom of incline with same speed.

Acceleration of 'A' will be greater than acceleration of 'B' when both are released to slide on inclined plane

answer is B, C.

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Detailed Solution

A : Work done by gravity is same for motion from A to Z and B to M for equal mass. So K.E. will be equal.
B : Acceleration $= gsin θ$
C: W_g + W_ext = 0 (Because moved slowly)
W_ext = -W_g
W_g is positive so W_ext < 0