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Two identical blocks A and B are resting on a smooth horizontal surface given equal speeds of 2 m/s in opposite sense as shown in the figure.
At t = 0, the position of blocks are shown, then the coordinates of centre of mass t = 3 s will be

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(3,0)

(5,0)

(2.25,0)

(1,0)

answer is D.

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Detailed Solution

At t = 0, centre of mass is at mid- point or at (2.25 m, 0)

$V_{C O M} = \frac{m_{1} v_{1} + m_{2} v_{2}}{m_{1} + m_{2}} = \frac{(4 x 2 + 4 x (- 2))}{4 + 4} = 0$
Velocity of centre of mass is zero. Hence, centre of mass will remain at this position all the time.

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