Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Two identical bodies are made of a material for which the heat capacity increases with temperature. One of these is at 1000C, while the other one is at 00C. If the two bodies are brought into contact, then assuming no heat loss, the final common temperature is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

00C

b

500C

c

more than 500C

d

less than 500C but greater than 00C

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Let θ be the final common temperature. Further let sc and sb be the average heat capacities of the cold and hot(initially) bodies respectively (where sc < sh given)

From, principle of calorimetry,

heat lost = heat gained

%   θ = sh(sh+sc)×1000C = 1000C(1+scsh)

scsh<1           1+scsh<2

θ > 1000C2 or θ > 500C

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring