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Two identical bulbs A and B are designed for the same voltage. Their power is rated $P_{A}$ and

$P_{B}$ respectively where $P_{B} > P_{A}$ . They are joined in series across a V voltage supply then

when a bulb will draw more power.

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A will draw more power than B

B will draw more power than A

The ratio of powers drawn by them will depend on V

A and B will draw the same power

answer is B.

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Detailed Solution

Two identical bulbs A and B are designed for the same voltage. Their power is rated

P_{A}

and

P_{B}

respectively where,

P_{B} > P_{A}

. They are joined in series across a V voltage supply then
when bulb B will draw more power than bulb A.

R = \frac{V^{2}}{P}

The bulb with a higher power rating has less resistance and vice versa. When the
bulbs are joined in series, they draw the same current.

P = I^{2} \times R

The bulb with the lower power rating draws more power.

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