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Two identical capacitors are charged individually to different potentials and connected parallel to each other. After disconnecting them from the source:

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The net energy stored in the two capacitors is less than the sum of the initial individual energies

Net charge on connected plates is less than the sum of initial individual charges

Net charge on connected plates equals the sum of initial charges

The net potential difference across them is different from the sum of the individual initial potential differences

answer is B, C, D.

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Detailed Solution

$V_{cm} = \frac{C_{1} V_{1} + C_{2} V_{2}}{C_{1} + C_{2}}$
Apply KVL in the loop, $\frac{- Q_{2} - q}{C} + \frac{Q_{1} - q}{C} = 0$

$q = \frac{Q_{1} - Q_{2}}{2}$

Isolated connected plates have same charge, they are only distributed differently after connection.
$ΔU = \frac{1}{2} {CV}_{1}^{2} - \frac{1}{2} (2 C) {(V_{CM})}^{2}$
Energy is lost during sharing of charges, due to current flowing in the circuit.

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