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Two identical capacitors are connected in series. Now a dielectric constant K is introduced to fill gap between plates of second capacitor by introducing a dielectric slab.

Column – I Column – II
A) Electric field between plates of first capacitor P) Increases
B) Force between plates of second capacitor Q) Decreases
C) Potential difference between points X and Y R) Constant if $C_{1} = C_{2}$
D) Ratio of energy stored in first capacitor and second capacitor S) Constant if $C_{1} = k C_{2}$
T) Unpredictable

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$A - q; B - p; C - s; D - r$

$A - q; B - p; C - r, s; D - p$

$A - q; B - r; C - s; D - p$

$A - p; B - p; C - r, s; D - p$

answer is A.

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Detailed Solution

$C_{2}' = k C_{2}$ (increases)
$V_{2}' < V_{2}, V_{1}' > V_{1}$
. $\Rightarrow E_{1}' > E_{1}$ $\Rightarrow p$
Force between plates $= \frac{Q^{2}}{2 A ε_{0}}$
$C' > C \Rightarrow Q' > Q$
$\Rightarrow$ Force increases
Potential difference between points $X$ and $Y$ is equal to e.m.f. of cell
Ratio of energy stored $= \frac{C_{2}}{C_{1}}$
$C_{2}' > C_{2} \Rightarrow$ Ratio increases

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