Two identical cars A and B are moving at 36 kmph. A goes on a bridge, convex upward and ‘B’ on concave upward. If the radius of curvature of bridge is 20 m, the ratio of normal forces exerted on the cars when they are at the middle of bridges (g = 10 ms^–2)

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1 : 5

2 : 3

1 : 3

1 : 2

answer is A.

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Detailed Solution

$N_{convex} = mg - \frac{{mv}^{2}}{r} = m (10) - m (\frac{100}{20}) = 5 m$

$N_{concane} = mg + \frac{{mv}^{2}}{r} = 10 m + 5 m = 15 m$

$\frac{N_{convex}}{N_{concane}} = \frac{5 m}{15 m} = 1 : 3$

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