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Q.

Two identical cells each of emf 1.5V are connected in series across a 10Ω resistance. An ideal voltmeter connected across 10Ω resistance reads 1.5V. The internal resistance of each cell is___Ω.

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answer is 5.

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Detailed Solution

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Let the internal resistance of a cell be 'r', 

the current in the circuit is given by i=3(10+2r)

The potential difference across the resistance is given by 3×10(10+2r)=1.5⇒r=5Ω

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