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Q.

Two identical cells each of emf 1.5V are connected in series across a 10 $Ω$ resistance. An ideal voltmeter connected across 10 $Ω$ resistance reads 1.5V. The internal resistance of each cell is___ $Ω$ .

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answer is 5.

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Detailed Solution

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Let the internal resistance of a cell be 'r',

the current in the circuit is given by $i = \frac{3}{(10 + 2 r)}$

The potential difference across the resistance is given by $\frac{3 \times 10}{(10 + 2 r)} = 1.5 \Rightarrow r = 5 Ω$

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