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Two identical cells each of emf 1.5V are connected in parallel across a parallel combination of two resistors each of resistance 20 $Ω$ . A voltmeter connected in the circuit measures 1.2V. The internal resistance of each cell is

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2.5 $Ω$

4 $Ω$

5 $Ω$

10 $Ω$

answer is C.

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Detailed Solution

$\begin{array}{l} V = E - \frac{i r}{2} \\ 1.2 = 1.5 - i (\frac{r}{2}) \\ i (\frac{r}{2}) = 0.3 \\ i = \frac{1.5}{10 + \frac{r}{2}} \Rightarrow i = 0.12 A \\ r = 5 Ω \end{array}$

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