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Q.

Two identical charged spheres suspended from a common point by two massless strings of lengths l, are initially at a distance d (d << l) apart because of their mutual repulsion. The charges begin to leak from both the spheres at a constant rate. As a result, the spheres approach each other with a velocity v. Then v varies as a function of the distance x between the spheres, as :

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a

Vx

b

Vx12

c

Vx12

d

Vx1

answer is C.

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Detailed Solution

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Question Image

tanθ=Femgθ

Kq2x2mg=x2

 or x3q2....1

 or x3/2q2

 differentiate eq.(i) w.r.t. time 

3x2dxdt2qdqdt but dqdt is constant 

 so  x2(v)q

x2(v)x3/2 or vx1/2

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