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Two identical charges repel each other with a force equal to 10 mg wt when they are 0.6 m apart in air, $(g = 10 m s^{- 2})$ . The value of each charge is

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$2 \times 10^{- 7} C$

$2 m C$

$2 n C$

$2 μ C$

answer is D.

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Detailed Solution

$F = \frac{1}{4 π ε_{0}} \frac{q_{1} q_{2}}{d^{2}}$

$∴ (10 \times 10^{- 3}) \times 10 = \frac{(9 \times 10^{9}) \times q^{2}}{{(0.6)}^{2}}$

$\Rightarrow q^{2} = 4 \times 10^{- 12}$

$\Rightarrow q = 2 \times 10^{- 6} C = 2 μ C$

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