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Two identical coils, each of self-inductance L, are connected in series and are placed so close to each other that all the flux from one coil links with the other. The total self-inductance of the system is

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answer is D.

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Detailed Solution

$M = \sqrt{L_{1} L_{2}} = L$

$L_{e f f} = L_{1} + L_{2} + 2 M$

= L + L + 2L = 4L

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