Two identical conducting ring A and B of radius R are in pure rolling over a horizontal conducting plane with same speed (of center of mass) v but in opposite direction. A constant magnetic field B is present pointing inside the plane of paper inside dotted area. Then the potential difference between the highest points of the two rings, is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

4BvR

2BvR

Zero

3BvR

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Considering a projected length 2R on the ring in vertical plane. This length will move at a speed v perpendicular to the field.
Question Image
This results in an induced emf: $e = Bv (2 R)$ in the ring
In Ring $" A ": e_{A} = B (- V (2 R)$ In Ring $" B ": e_{B} = B (V) (2 R)$
Thus, $e_{B} - e_{A} = 4 BVR$
Note- There will be no potential difference across a diameter due to rotation.