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Q.

Two identical conducting ring A and B of radius R are in pure rolling over a horizontal conducting plane with same speed (of center of mass) v but in opposite direction. A constant magnetic field B is present pointing inside the plane of paper inside dotted area. Then the potential difference between the highest points of the two rings, is
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a

4BvR

b

2BvR

c

Zero

d

3BvR

answer is C.

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Detailed Solution

Considering a projected length 2R on the ring in vertical plane. This length will move at a speed v perpendicular to the field. 
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This results in an induced emf:  e=Bv(2R) in the ring
In Ring  " A":eA=B(V(2R) In Ring "B":eB=B(V)(2R)
Thus, eBeA=4BVR
Note- There will be no potential difference across a diameter due to rotation.  

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